That’s precisely it. Remember, strong bases can be just as toxic and corrosive as strong acids. your standard sodium carbonate solution dilute hydrochloric acid to standardise phenolphthalein indicator solution methyl orange indicator solution Methods 1. The carbonic acid rapidly breaks down to give carbon dioxide and water, leaving the solution neutral. Titrate with the hydrochloric acid. Imagine this, if you added too much NaOH to the acid, then the resulting solution would become strongly basic. Hydrochloric acid is acidic, meaning that it releases protons (H⁺) when dissolved in water. When combined, aqueous solutions of sodium carbonate and hydrochloric acid generate an acid-base reaction. ( Acid + Base -> Salt + Water ). Sodium carbonate and Hydrochloric acid, after a reaction, give Sodium chloride, Water, and Carbon dioxide as products. 2. Write and balance the chemical equation and then calculate; "how many moles of HCl are required to react with 0.050 moles of sodium carbonate?" The chemical equation for the reaction of sodium carbonate and hydrochloric acid is given as: Ionic form of the above equation follows: As, sodium and chloride ions are present on both the sides of the reaction. The reaction is as follows - NaHCO3(aq) + HCl(aq) -> NaCl(aq) + H2O(l) + CO2(g) This is an example of a neutralization reaction. Add a few drops of phenolphthalein indicator solution. Transfer a 25cm 3 aliquot (portion) of your sodium carbonate solution to a 250cm3 capacity conical flask. Sodium carbonate is a basic compound, meaning that it generates hydroxide ions (OH⁻) when dissolved in water. Thus, it will not be present in the net ionic equation and are spectator ions. The products formed are - NaCl(Sodium Chloride), Water and Carbon-dioxide. Sodium carbonate (Na2CO3) reacts with hydrochloric acid (HCl) to give sodium chloride (NaCl) and carbonic acid (H2CO3).

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